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# How fast does a 275 -m spaceship move relative to an observer who measures the ship's length to be 155 $\mathrm{m}$ ?

## $0.83 c$

Quantum Physics

### Discussion

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LB
##### Farnaz M.

Simon Fraser University

##### Aspen F.

University of Sheffield

### Video Transcript

So this question We have to use the length contractor formula to the equation. In those photos, the contracted link is equals to the proper length. Times square root off one minus the divided by C squared. Now we have to solve this equation for V divided by sea. Then we square both sides. So l squared is it was toe l zero square times one minus we better by sea. It's weird. Then send this term to the other side to get l divided by l zero square is equal to one minus the divided by C squared. Then we said this term to decide in this term to decide together divided by sea squared is equal to one minus l divided by l zero squared Now take the square root to finally get the divided by sea has been equals to one miners l divided by yelled zero squared. Now we have to plug in the vials that were given in the problem. So l is the contracted link and l zero is the proper thing as given by the question, the proper ling is 275 meters and the contractor bling is 155 meters. So re divided by C is equal to the square. Root off one miners, uh, 155 divided by 275 square. And these gives us approximately 0.8 free. Then the is the coast to 0.8 free time seat.

Brazilian Center for Research in Physics

#### Topics

Quantum Physics

LB
##### Farnaz M.

Simon Fraser University

##### Aspen F.

University of Sheffield