How is conformational analysis used to explain the $6: 1$ ratio of trans-to cis-2-butene formed on dehydrochlorination of 2 -chlorobutane?
For either enantiomer there are two conformers in which the $\mathrm{H}$ and $\mathrm{Cl}$ eliminated are anti to each other. Conformer I has a less crowded, lower-enthalpy transition state than conformer II, Its $\Delta H^*$ is less and reaction rate greater; this accounts for the greater amount of trans isomer obtained from conformer I and the smaller amount of cis isomer from conformer II.