00:01
All right, so problem nine, how many possible aldohephtosis can we have? and how many of those would be in the d configuration and how many would have the l configuration.
00:15
Okay, so the number of possible sugar depends on how many chyron centers it has.
00:23
Okay, so although heptosis has seven carbons, first of all, right? it starts with that aldehyde, cho, and then it goes all the way to the seventh carbon, which is ch2oh.
00:37
And then you'll have five carbons in between.
00:39
We got one, two, three, four, five.
00:42
Okay.
00:43
So all these, all these five carbons are chiral centers...