00:01
All right, this problem is going to just really be asking us to do mole conversions.
00:06
And we have to come up with some of these conversion factors.
00:10
So they're a little bit different than some of the easier dimensional analysis you probably did at the beginning of the year.
00:17
We have 0 .125 moles of f -e -t -i -o -3.
00:26
I want to know how many moles and then atoms this has of titanium.
00:34
Okay.
00:35
So that's what we have to figure out how to get to.
00:38
In order to do that, you can very simply look at the compounds in one mole of f .e.
00:49
Ti -o -3.
00:52
How many titaniums are there? there's no subscript next to the t -i in the compound, which means i only have one.
01:03
Okay.
01:04
That gets me to moles of titanium.
01:07
I can cancel out moles of feti .03, i'm currently in moles of titanium, right? in order to get from moles into atoms, i can then take that and do 6 .022 times 10 to the 23rd.
01:23
This is atoms of titanium, and we're going to put it over one mole.
01:30
Remember, this is avagadro's number.
01:32
Avogadro's number by definition is 6 .022 times 10 to the 23rd of whatever you happen to be left.
01:40
At, whether it's atoms, molecules, cupcakes, whatever.
01:47
This allows me to cancel out my moles of titanium, and i'm left with atoms of titanium.
01:54
Now, i understand writing out all of this work is tedious, but it is something that i highly recommend that you do so that you can follow your units, and it will help you in the long run.
02:06
When we solve this, 0 .125 times avagadro's number of 6 .022 times 10 to the 23rd.
02:12
I get 7 .53 times 10 to the 22 atoms of titanium.
02:22
The second compound that they want us to use is titanium for chloride.
02:30
So this requires you to remember a little bit of naming.
02:33
When you see a compound that has those roman numerals, it means that there is a 4 plus charge, right? ivy is 4 in roman numerals.
02:41
All of these are cat ions.
02:44
Or positive ions.
02:46
So that four in roman numerals means that the titanium has a four plus charge.
02:52
Chloride came from chlorine.
02:55
That is in group 7a.
02:56
Hopefully you remember that that is a minus one charge.
03:00
So if i'm crossing these charges, this is really a one, a negative one charge for the chlorine.
03:08
That's going to come down as a subscript for titanium.
03:11
The four comes down as the subscript for the chlorine.
03:15
And this compound becomes ticl4...