00:01
So here we use the formula pv equals to nrt to solve the problem.
00:11
Okay, so let's first write out the reaction equation for f .e .203 being converted to elemental iron and oxygen.
00:29
So for two moles of f .e .203, we can obtain four modes of f .e .203, we can obtain four most, of fe plus 3 moles of oxygen.
00:45
So the molar ratio between iron oxide and oxygen is 2 to 3.
00:54
And here we are targeting to convert one ton of fe 203 into oxygen and 1 tonne equals to 907 185 gram.
01:25
And convert the weight to mole, we can divide 907 -185 gram by the molecular weight of iron oxide, which is 159 .69 grams per mole.
01:56
And will obtain the result of 56 81 more.
02:05
However, that's the molar amount of fe203.
02:12
As for oxygen, we divide 5681 by 2 and times 3, which equals to 85, 21, which is equal to n in the formula.
02:55
Now we know the n which is equal to 85, 21 mole, and r equals to 0 .0 821, liter, atomic pressure, over mole, and temperature in kelvin...