00:01
How many geometric portions are possible? the terms containing 48, 27 and 64.
00:06
So we can select this is the 48, it's the ph term.
00:11
This is a f u.
00:12
This is the rth term, the gp.
00:15
So we have common ratio is up.
00:20
A is the first term.
00:26
If we just work on this, we have a, r to the part p, negative 1, that equals 48.
00:33
Next, a, r to the part 2, negative 1, that equals 0 .27.
00:37
Next a r to the power r negative one that equals 64 this we get now so what you can do now just to clear this equation by this equation so you get a r to the power r negative over a r to the part p negative one that equals 24 over 48 that will be 4 over 3 so from here you get r to the part r negative p equals 4 over 3 so we go next we do this equation by this equation so we get r to the part r negative q that equals to 4 over 27 so that's going to be 4 over 3 all cube this we go if you compare this two equation this question 1 and equation 2 if you compare this two equation so we get r to the part i'm sorry r of the part r negative q small r negative q i add to the part small a negative cube that we get r to the power smaller negative q that we get equal to we will have a here we have four over three right so four over three that to the part r negative fee that will be r to the part three times r negative three that we get here just compare now we'll have r negative q plus three r i'm sorry r negative q equals we have equals three r negative 3p or from here we have two are negative 3p positive q equal to we've got an equation here with three variables three unknowns we define the number of geometric progression possible let's take any value let's take uh let's say so it's pqr if it takes here qs 5 r s 10 let me solve this we get it as uh 20 negative 3p and positive 5 equals 0.
02:58
So i get at 25 negative 3 p is equal to 0.
03:05
I'll run in this way.
03:06
But p is not coming up to be an integer.
03:09
So let's write some more values here.
03:11
Because it's coming up to be infinite number of solutions.
03:13
We have three and no and one equation that lead to infinite number of solutions...