00:02
Hi there.
00:04
In this problem, i want to start off with the balanced equation.
00:08
We have graphite reacting with oxygen to produce carbon dioxide.
00:18
And of course, the oxygen is a gas and the carbon dioxide is a gas.
00:23
We also know we're working at one atmosphere of pressure and zero degrees celsius.
00:28
Or in other words, standard temperature and pressure.
00:34
We would like to react 42 .5 liters of the oxygen.
00:41
And we want to know how many grams of carbon, how many grams of the graphite, it's going to take to react all 42 .5 liters of this oxygen.
00:51
This is a stoichiometry problem.
00:53
We're going to start with what is given, which is the 42 .5 liters of oxygen.
01:02
Let's go ahead and plan this out real quickly before i continue.
01:05
So if i have liters of oxygen at stp, in my first step, i can convert to moles of oxygen by dividing by 22 .4.
01:16
22 .4 is the molar volume of any gas when you're at stp.
01:21
That will give me to moles of oxygen.
01:23
Then i can use the mole ratio from this balanced equation to convert to moles of carbon...