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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81

Problem 19 Medium Difficulty

How many grams of coffee must evaporate from 350 g of coffee in a 100-g glass cup to cool the coffee from $95.0^{\circ} \mathrm{C}$ to $45.0^{\circ} \mathrm{C}$? You may assume the coffee has the same thermal properties as water and that the average heat of vaporization is 2340 kJ/kg (560 cal/g). (You may neglect the change in mass of the coffee as it cools, which will give you an answer that is slightly larger than correct.)

Answer

33.10042735 $\mathrm{g}$

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Physics 101 Mechanics

College Physics for AP® Courses

Chapter 14

Heat and Heat Transfer Methods

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Problem 15
Problem 16
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Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
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Problem 40
Problem 41
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Problem 48
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Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
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Problem 81

Video Transcript

so to solve this question, we need to first find what a question one must use, so we must use the question off. Q. Equal to mass times latent heat off vaporization. This is where you'll find them as from, but we don't know. Value of Q. It, uh, that can be found by using the fact that vaporizing this amount of coffee reduces the coffee's temperature overall, plus the glasses temperature by 15 to the senses. That is 95 to 45 So that must be emcee Delta T off glass plus M. C. Delta T off coffee. So we need to quit these two quantities to find this value. The mass now will be equal to M G C G plus M. C. See subsea times Delta T divided by off vaporization. So let's substitute on the values Mass is equal to M G, which is glass 0.1. Glass has specific it off. 8 40 Jules Tuberculosis pedigree Celsius. Plus we need to write the mass off coffee, which is 3 50 times. Specifications it Now we will assume it's full. 186 Same as water on change in temperature, as we know is 53 Celsius, divided by the Layton's Heat, which is 32340 kilo. Jules, it's a two thing for zero times 10 Power three Killer Jules per kilograms. Let's calculate this 0.1 times 8 40 plus 3 50 times. Okay, let me put it this year this should be 0.3 53 50 because it's in terms of crimes. So for 186 I went to about 15 divided by 2340 So the answer here is 33.1 times 10 power negative, three kilos. So this is 33.1 God. So we need to up evaporate this much amount of coffee to reduce the temperature to 45 degrees. This answer is slightly larger, because why we used this equation here? These values here, especially here 0.3 50. We know that this mass of coffee is decreasing when this is evaporating. So final mass of coffee is less than 0.35 which is approximately 0.317 That's the final mass of coffee, so but that is quite small compared to 3 50 33 So compared to 3 50 33 small, which is approximately 10% off a value. So our answer will not be ways different. It will be larger, but not much. Thank you.

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