00:01
In this problem, you have a solution of 35 grams of ethylene glycol, h -o -ch2 -ch2 -o -h, dissolved in 500 grams of water.
00:22
The problem asks you to find the vapor pressure of the solution at 32 degrees celsius.
00:29
The vapor pressure of pure water at 32 degrees celsius is equal to 35 .7 mm.
00:43
Mercury.
00:50
Ethylene glycol is a non -volatile liquid, which means it won't contribute to the vapor pressure at all.
00:56
According to rout's law, the vapor pressure of any solvent with something dissolved in it is equal to the mole fraction of the solvent times the vapor pressure of the pure solvent.
01:25
So we can use this law to solve for the vapor pressure of the solution.
01:32
So as is given in the problem, the vapor pressure of pure h2o is going to be 35 .7 millimeters mercury.
01:47
The mole fraction of the solvent h2o is going to be equal to the moles of water over the total moles in the solution, which is moles of water, plus.
02:07
Moles of ethylene glycol.
02:20
We can use the given masses to solve for the mole fraction...