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How many grams of fructose, $\mathrm{C}_{\mathrm{6}} \mathrm{H}_{12} \mathrm{O}_{6}$ are in 1 $\mathrm{L}$ of soft drink if the molarity of fructose in the soft drink is 0.75 $\mathrm{M} ?$

135 grams

Chemistry 102

Chemistry 101

Chapter 15

Toxins in Solution

Section 3

Preparing Solutions

Solutions

Composition

Chemical reactions and Stoichiometry

Carleton College

University of Central Florida

Rice University

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in problem six. How many grams of fructose are involved later Off soft drink if modularity or fructose in soft drink is 0.75 So fructose is C six actual or six. So this is the fructose. So we find out the weight off this factors So okay, Now McGarity is given That is zero point 75 Mueller and volume is also given. That is one later. So as we know that the morality is defined as the number off moles so number off malls off salute and salute is the factors in this case divided by the volume off solution in leaders and number off moles is equal toe Wait our molecular weight. So the molecular weight off fructose. So the molecular weight off practices molecular weight off fructose. That s C six at 12 or six. So as we know, carbon is 12 and hydrogen is one. Oxygen is 16. So we get six in 2. 12. Last 12 in 21 last six in 2 16. So, on solving this value, we get molecular weight. Off fructose is one dirty cram Permal. So 1 80 g per mole is theme molecular weight, off fructose Okay, We can put this value and I'll find the molecular. Find the weight off practice. So w by 1. 80. Now put all the value in the this equation. Moderate equation. So 0.75 physical toe off. Wait. Our molecular weight is 1 80 it is said that it is a one letter solution. So on solving we get weight is 1 35 g. So that means we can say that the weight off fructose is 1 35 g. So wait off practice. Will it offer across? That is C six h 12. 06 So this is the formula. Factors is 1 35 graham in one letter off soft drink. If McGarity off practice in soft drink is zero point $75 so our answer is 1 35 grand.

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