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How many grams of gas are present in each of the following cases?

(a) 0.100 $L$ of $CO_{2}$ at 307 torr and $26^{\circ} \mathrm{C}$(b) 8.75 $L$ of $\mathrm{C}_{2} \mathrm{H}_{4},$ at 378.3 $\mathrm{kPa}$ and 483 $\mathrm{K}$(c) 221 $mL$of $\mathrm{Ar}$ at 0.23 $\mathrm{torr}$ and $-54^{\circ} \mathrm{C}$

a) 0.0726 $\mathrm{g}$b) 23.115 $\mathrm{g}$c) $1.478 \times 10^{-4} \mathrm{g}$

02:40

Aadit S.

Chemistry 101

Chapter 9

Gases

The K.

December 28, 2020

How many grams of gas are present in the each of the following cases?

Rice University

Drexel University

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going to look at the ideal gas equation. So what we have is PB equal on rt. So we're arranging for moles and is equal to P B over party. So what we're doing is just plugging some numbers in. So we have no 0.4. There were four atmosphere pressure multiplied by no 0.100 leases volume all divided by no point No. 8 to 1 atmosphere. Paletta mold minus one. Calvin's minus one. Most were by 299 Calvin That's what temperature Miles is. Not quite not No. 165 and then we want to determine the massive co two. So we multiply the malls by the molecular weight to multiply No point no No. 1655 44.1 grounds bomb Alz minus wahm co two mass equal to no point No seven, 26 g. So in the second part, we've got a very similar calculation to carry out. So again we're determining the moles. So this calculation will look like 3.734 atmosphere well supplied by 8.75 liters. That is all divided by not 0.98 to bomb atmosphere Paletta mall minus one Kelvin's minus one multiplied by 483 Calvin temperature moles is equal to no 0.8 to 4 miles. Multiply that by molecular weight off C two h four, which is 28.52 grams per mall. So mass C two h four equal to 23.115 g. Yeah, so we've got one last example to cover that is very similar to this. So began the same calculation that we did on the first page in full. So we have moles is equal to not point not 372 times 10th minus four for Aga. So then we multiply this by the molecular weight have all gone That is 39.978 g per mall minus wealth. The mass of all gone is equal to 1.478 times 10 to the minus 4 g

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