00:01
In this problem, we are asked to find how many grams of hydrochloric acid are consumed in the reaction of 425 grams of a mixture containing 35 .2 % magnesium carbonate and 64 .8 % magnesium hydroxide by mass.
00:15
This problem involves two chemical reactions.
00:18
We can start this problem by finding the amount of hydrochloric acid that will react with both of the species.
00:24
We were told in the problem statement the percent by mass of the 425 grams of each of these species.
00:30
Substances.
00:32
So we can multiply our total sample weight by the percentage by mass of each of our individual species.
00:39
So we find that we have 275 .4 grams of our magnesium hydroxide, and we have 149 .6 grams of our magnesium carbonate.
00:51
So we can go ahead and solve for the amount of moles of hydrochloric acid that need to react with this amount of both our magnesium hydroxide and magnesium carbonate.
01:04
And then we'll go ahead and add those moles together to find the total moles of hydrochloric acid required.
01:10
We can start with our magnesium hydroxide here and divide by the molar mass to get it in terms of moles of our magnesium hydroxide.
01:25
And we have stoichiometry from our first chemical reaction shown above...