00:01
In this problem, we're considering a 50 mil aliquot of a solution that contains a solution of edta.
00:09
This solution contains 0 .45 grams of magnesium sulfate in 500 liters of water.
00:17
It required 37 .5 milliliters of edta for titration.
00:22
We're asked to find how many milligrams of calcium carbonate will react with one millimeter of this solution.
00:28
So our first order of business will be to find the molarity of the edta and then find out how many milligrams will be required or how many milliliters could be titrated with one millimeter of that solution.
00:47
Okay.
00:49
So let's figure out what we've got here.
00:57
We have, okay, we've got our moles of magnesium sulfate.
01:09
We have 0 .45 grams, and we were told we had one, what was it, 120 .37 grams per mole.
01:25
That'll give me 0 .30303, 37 around later.
01:38
Okay, and then that's how many moles.
01:51
So i've got 0 .0037 -385 moles.
01:59
In half a liter and then i have a 50 mil aliquot and that'll give me 0 .000 37385 moles of magnesium sulfate so i've got moles of eda equals our moles of magnesium sulfate or magnesium i'm going to worry about i'm going to make a note also calcium moles for reference later.
02:57
Therefore, i will have the malaria of the edta.
03:06
0 .000 -3735 moles divided by 0 .035 liters.
03:25
And that equals, i want to make sure i copied that down.
03:36
376...