Question
How many $\mathrm{mEq}$ of $\mathrm{Ca}^{+}$are available in $1200 \mathrm{~mL}$ of a solution of calcium chloride containing $1.5 \mathrm{mg} / \mathrm{mL}$ of $\mathrm{Ca}^{+}$?
Step 1
Given that the solution contains 1.5 mg/mL of Ca$^{+}$ and the total volume of the solution is 1200 mL, we can calculate the total amount of Ca$^{+}$ in the solution: Total amount of Ca$^{+}$ = 1.5 mg/mL $\times$ 1200 mL = 1800 mg Show more…
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