Given that the solution has a strength of $1.5 \, \mathrm{mg/mL}$ and a volume of $400 \, \mathrm{mL}$, we can calculate the total amount of calcium chloride in the solution:
$1.5 \, \mathrm{mg/mL} \times 400 \, \mathrm{mL} = 600 \, \mathrm{mg}$
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