Question
How many $\mathrm{mEq}$ of $\mathrm{Na}^{+}$are in $360 \mathrm{~mL}$ of $16 \%$ solution of sodium cyclamate $($ molecular weight $=201.33 \mathrm{~g} / \mathrm{mol}$, valence $=1$ )?
Step 1
Given that the solution is 16% sodium cyclamate, we can calculate the amount of sodium cyclamate in the solution as follows: Amount of sodium cyclamate = 16% of 360 mL Amount of sodium cyclamate = 0.16 * 360 mL Amount of sodium cyclamate = 57.6 mL Show more…
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Some Basic Concepts of Chemistry
Topic 2 : Stoichiometry, Equivalent Concept, Neutralization and Redox Titration
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