Question
How many $\mathrm{mEq}$ of potassium sulfate $\left(\mathrm{K}_2 \mathrm{SO}_4\right.$, molecular weight $\left.=174\right)$, are available in $3.480 \mathrm{~g}$ of potassium sulfate?
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A solution was prepared by dissolving 521 mg of potassium sulfate (K2SO4, MW = 174.24 g/mol) in 513 mL of water. Use this information to calculate each quantity: moles of K2SO4 = 0.00299 mol millimoles of K2SO4 = 2.99 mmol F = [K2SO4] = [K+] = [SO4^2-] = ppm K2SO4 = %(w/v) K2SO4 = pK+ = pSO4^2- =
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