Question
How many milligrams of calcium chloride $\left(\mathrm{CaCl}_2\right.$, molecular weight $=$ $111 \mathrm{~g} / \mathrm{mol}$ ) are needed to prepare $750 \mathrm{~mL}$ of solution containing $10 \mathrm{mEq} / \mathrm{L}$ of $\mathrm{Ca}^{+2}$ ?
Step 1
The molar mass of CaCl2 is 40.08 g/mol (for Ca) + 2(35.45 g/mol) = 110.98 g/mol ≈ 111 g/mol. Show more…
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