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How many milliliters of a $0.1500-M$ solution of KOH will be required to titrate 40.00 $\mathrm{mL}$ of a $0.0656-\mathrm{M}$solution of $\mathrm{H}_{3} \mathrm{PO}_{4} ?$$\mathrm{H}_{3} \mathrm{PO}_{4}(a q)+2 \mathrm{KOH}(a q) \longrightarrow \mathrm{K}_{2} \mathrm{HPO}_{4}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)$

34.99 $\mathrm{mL}$

Chemistry 101

Chapter 4

Stoichiometry of Chemical Reactions

Chemical reactions and Stoichiometry

University of Maryland - University College

University of Kentucky

University of Toronto

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discussion says, for asks how many milliliters of a 0.15 Moeller solution of potassium hydroxide will be required to titrate 40 mills of a 400.656 Miller solution of each three people. Four. And gives his bounds chemical equation that I've written here. So it started with what we know about the acid tells us that we have 40 mills. We'll write that on leaders because that's the units that polarity is in. Is your four leaders of H three appeal for And it tells us the concentration is point 06 56 Moeller, which is points your six by six moles of the acid over one leader each. Three people for that would convert between moles age three people for and passing hydroxide himself in bounds. Chemical equation You see that one mole each three people for combines with two moles of potassium hydroxide And so we should be able to cancel unit's leaders each. Three people are moles h three people for like with moles of college. We do this. We would get 30.0 zero 52 moles of college. Then we can figure out what volume of the port 15 Miller solution will get us that money moles. Let's write this out. We have 0.15 more solution. Okay? Which and that would equal the number of moles. We just calculated that we need 1005 to goals of Ko age and some volume of that are rated as acts. Some number of leaders of K O H. That is one type of will get us that number of bulls. So say it again. Uh, this is number of moles we need and we can calculate the volume of the stock solution were given to figure out how many leaders we need to reach that number of moles. So if you re arrange to get X by itself, you would find the number of leaders. If you convert to the leaders the most. By my 1000 is 34.99 No leaders ko each passing hydroxide

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