Question

How many moles of anions are in 35.6 $\mathrm{g}$ of $\mathrm{AlF}_{3} ?$

   How many moles of anions are in 35.6 $\mathrm{g}$ of $\mathrm{AlF}_{3} ?$

Chemistry

John E. Mcmurry,… 6th Edition

Chapter 3, Problem 51

Instant Answer

Solved by Expert Nadia Lara

04/25/2020

Step 1

We know that the molar mass of $\mathrm{AlF}_{3}$ is 83.98 g/mol. We can use this to convert the mass of $\mathrm{AlF}_{3}$ we have into moles using the formula: \[ \text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}} \] Show more…

Show all steps

lock

Thanks for your feedback!

How many moles of anions are in 35.6 $\mathrm{g}$ of $\mathrm{AlF}_{3} ?$

Play audio

Feedback

Powered by NumerAI

Nadia Lara and 71 other subject Chemistry 101 educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Mole Concept

The mole is a fundamental counting unit in chemistry that represents 6.022 x 10^23 of a specified particle (such as atoms, molecules, or ions). It allows chemists to relate masses of materials to the number of constituent particles using Avogadro's number.

Molar Mass

Molar mass is the mass of one mole of a substance, calculated by summing the atomic masses of all atoms in the chemical formula. It is essential for converting a mass of a substance into the number of moles, thereby enabling quantitative analysis.

Stoichiometry

Stoichiometry is the study of the quantitative relationships between reactants and products in a chemical reaction. It uses balanced chemical formulas to determine mole ratios, which are used to convert between the number of moles of various substances in a reaction.

Chemical Formula Interpretation

Interpreting a chemical formula involves understanding the types and ratios of atoms present in a compound. It is crucial for identifying how many ions or atoms are produced per formula unit, which is necessary when determining the number of anions or cations formed by the compound.

Recommended Videos

Transcript

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later