00:02
Hi, in this problem, we are given a molecule that is tetra cyanothylene.
00:07
We have to tell the number of sigma bonds and pi bonds that are there in the molecule out of the given options a, b, c and d.
00:16
Now first of all, let's understand how many pi bonds and sigma bonds are presenting each type of covalent bond.
00:24
If a single covalent bond is present, this contains one sigma bond.
00:30
If a double covalent bond is present, it contains one sigma and one pi bond.
00:37
And in case of a triple covenant bond, whether it is carbon carbon or carbon nitrogen, it contains one sigma and two pi bonds.
00:47
Now, we will write the structure of this compound that can be shown as n triple bond bonded to carbon, this side again and triple bond c.
01:01
And there is a double bond beside the carbon which is further bonded to two c in groups, that is carbon, triple bond nitrogen.
01:11
Now we have all the bones shown in the given structure.
01:15
We will see the number of sigma and pi bonds.
01:18
Now carbon nitrogen bond here is a triple bond so it contains one sigma bond and two pi bonds.
01:27
In the same way, all the carbon nitrogen triple bond contains one sigma bond and two pi bonds each.
01:34
That is in this side, this scene group also has one sigma and two pi bonds.
01:41
Another scene group has one sigma and two pi bonds...