00:01
In this problem, we're looking at 2, 4 -dibromyl -3 -chloropentane.
00:06
So first let's draw that out, and then we'll talk about our stereoisomers.
00:10
So pent tells us 5 carbons.
00:13
In tells us we have all single bonds between carbons.
00:18
2, 4 -dibromyl means that carbon is 2, and 4, we have bromines.
00:24
And 3 -chloro means carbon 3, we have chlorine.
00:27
And here, we need to determine how many stereosceptors we have.
00:34
And remember, for a chiral carbon, we want four different groups coming off of that carbon.
00:42
So we can tell here and here we're going to have four different groups.
00:47
But we need to be careful here because it's really easy to say, ok, yes, there's two different groups coming off our main chain.
00:55
It must be chiral.
00:58
However, notice that this group and this group are exactly the same.
01:04
So we only have two stereocenters...