Question
How many tons of $\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}$ are necessary to prepare 5.0 tons of phosphorus if the yield is 90$\% ?$
Step 1
We can use the formula for moles which is mass divided by molar mass. Given that the mass of phosphorus is 5 tons (or 5000 kg) and the molar mass of phosphorus is 123.89 g/mol, we can calculate the number of moles as follows: \[ n_{P} = Show more…
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