00:01
Solving problem 34 of chapter 15.
00:07
So let's start from the molecule 1357 cycloneatatrin.
00:15
So 1 .357 cycloanatotrin.
00:29
So this means it's a cycle with nine carbons.
00:35
Let's try to draw it.
00:38
Two, three, four, five, six, eight, eight, and nine.
00:49
The bone lens should be all the same, but it's pretty difficult.
00:55
And then we have four tetra in four double bonds.
01:00
So let's put one in here.
01:02
If we number, so we have the positions.
01:05
So let's number as one, two, three, four, five, six, seven, eight, and nine.
01:16
So in position one, we have a double bond.
01:19
In position three, we have another double bond.
01:21
In position five, we have another bond.
01:24
In position seven, we have another double bond.
01:28
Okay, so the problem is asking how we can make this compound aromatic...