Question

How much above the surface of earth does the acceleration due to gravity reduce by $36 \%$ of its value on the surface of earth. Radius of earth $-6400 \mathrm{~km}$.

   How much above the surface of earth does the acceleration due to gravity reduce by $36 \%$ of its value on the surface of earth. Radius of earth $-6400 \mathrm{~km}$.

Practice Problem in Physics for the JEE Main and Advanced

Practice Problem in Physics for the JEE Main and Advanced

Abhay Kumar 2015 Edition

Chapter 8, Problem 1

Instant Answer

Solved by Expert Narayan Hari

01/23/2022

Step 1

Step 1: We know that the acceleration due to gravity on the surface of the earth is given by $g = \frac{G M_e}{R^2}$, where $G$ is the gravitational constant, $M_e$ is the mass of the earth, and $R$ is the radius of the earth. Show more…

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How much above the surface of earth does the acceleration due to gravity reduce by $36 \%$ of its value on the surface of earth. Radius of earth $-6400 \mathrm{~km}$.

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Key Concepts

Inverse-Square Law

The inverse-square law explains that gravitational acceleration decreases with the square of the distance from the center of a mass. It is crucial in understanding how changes in altitude above the Earth's surface lead to a reduction in the acceleration due to gravity.

Gravitational Acceleration Variation

Gravitational acceleration at a distance from a mass, such as the Earth, is derived from the law of gravitation and the inverse-square law. This concept explains that moving further away from the Earth's surface reduces the gravitational pull, allowing for calculations of the altitude at which gravity has decreased by a specified percentage.

Newton's Law of Universal Gravitation

This law states that every mass attracts every other mass through a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. It is fundamental in determining how gravitational forces change with distance from a mass like the Earth.

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