Question
How much energy can be stored in a spring with a spring constant of $500 \mathrm{N} / \mathrm{m}$ if its maximum possible stretch is $20 \mathrm{cm} ?$
Step 1
We know that 1 meter is equal to 100 centimeters. Therefore, we have: \[x_{\text{max}} = 20 \text{ cm} = 20/100 \text{ m} = 0.2 \text{ m}\] Show more…
Show all steps
Your feedback will help us improve your experience
Laszlo Zalavari and 90 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
How much energy can be stored in a spring with a spring constant of 500 N/m if its maximum possible stretch is 20 cm?
How much energy can be stored in a spring with $k=500 \mathrm{N} / \mathrm{m}$ if the maximum possible stretch is $20 \mathrm{cm} ?$
How much energy can be stored in a spring with k = 440 N/m if the maximum allowed stretch is 20 cm?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD