00:01
Here we're going to think through some quantitative things about treating a cell, a cancerous cell, and trying to kill those cells with high -energy photons coming from some x -ray device.
00:18
And so the specifics of the tumor are we're going to assume a density 10 to the 8 cells per cubic centimeter in the tumor.
00:29
And we are going to assume that the patient is going to be exposed to 70 units of dosage called the gray extended over 35 days, so two grays a day.
00:47
And the question is how much energy is going to be needed per cell? that's the question.
01:04
And why that would be useful is then we could think through how many m .e.
01:09
V photons need to be bombarded into the cell.
01:16
Okay, so first of all, it's good to know what a gray is.
01:19
So we'll start there.
01:20
That one gray is the same as one jewel of energy deposited per kilogram of material.
01:29
And we see that our dosage is going to be two grays per day.
01:35
And this is per day per exposure slash day.
01:47
Okay, and we're using two grays a day.
01:48
So we'll go ahead and multiply our mungray, which is two joules per kilogram.
02:02
And so we're going to set up a ratio to figure out our unknown jewels if we knew the mass of one cell.
02:21
Okay, so they give us the cell density.
02:24
And if we knew the mass density, we would be very close to figuring out the mass of one cell.
02:33
So one thing that's usually safe to assume about living tissue is the density is going to be close to water or one gram per cubic centimeter.
02:49
And so we know that one cell can be figured out using the density of cells times.
03:01
The inverse 1 cubic centimeter over 10 to the minus 8.
03:07
Sorry, 10 to the 8th.
03:11
I'm already trying to divide that through in my head.
03:17
So basically, that density is the same as 1 gram over 10 to the 8th cells.
03:32
And we can work that out that give myself some room.
03:39
I'm running out of room.
03:40
Is equal to x grams over one cell.
03:53
And so we can solve that for x, and we'll have the mass of one cell...