Question
How much heat is required to raise the temperature of $215 \mathrm{g} \mathrm{CH}_{3} \mathrm{OH}(1)$ from 20.0 to $30.0^{\circ} \mathrm{C}$ and then vapor-ize it at $30.0^{\circ} \mathrm{C}$ ? Use data from Table 12.3 and a molar heat capacity of $\mathrm{CH}_{3} \mathrm{OH}(1)$ of $81.1 \mathrm{J} \mathrm{mol}^{-1} \mathrm{K}^{-1}$
Step 1
We know that the molar mass of methanol (CH3OH) is approximately 32.04 g/mol. Therefore, the number of moles (n) can be calculated as follows: \[n = \frac{mass}{molar \, mass} = \frac{215 \, g}{32.04 \, g/mol} = 6.71 \, mol\] Show more…
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How much heat is required to raise the temperature of $215 \mathrm{g} \mathrm{CH}_{3} \mathrm{OH}(1)$ from 20.0 to $30.0^{\circ} \mathrm{C}$ and then vaporize it at $30.0^{\circ} \mathrm{C}$ ? Use data from Table 12.4 and a molar heat capacity of $\mathrm{CH}_{3} \mathrm{OH}(1)$ of $81.1 \mathrm{J} \mathrm{mol}^{-1} \mathrm{K}^{-1}$.
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