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How much heat is required to warm 1.50 kg of sand from 25.0 C to 100.0 C?
93900
Chemistry 102
Chemistry 101
Chapter 9
Thermochemistry
Thermodynamics
Chemical reactions and Stoichiometry
University of Central Florida
Rice University
University of Toronto
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So this question asks how much heat Q is required to heat one point five kilograms of sand from twenty five degrees Celsius to one hundred degrees Celsius, and so we can use the equation. Q Heat equals M, which is mass time CS, which is he capacity times Delta T. And so our CS in this case is for sand, which is zero point eight three five Jules per gram degrees Celsius. And then our delta T is one hundred minus twenty five since we have one hundred, which is our final temperature, and twenty five is our initial so finest final minus initial equals change. And so our change in temperature is seventy five degrees Celcius, and so are we want to convert our mass into Graham's so just multiplied by a thousand. And so now we just plug in these values so fifteen hundred grams times zero point eight three five jewels per gram, degrees Celsius times seventy five degrees Celsius and we get nine three, nine three seven point five jewels. And so to account for Sig Figs, we just around it to three sig figs and our final answer is nine three nine zero zero. Jules
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