00:08
So what we have here is we're taking a look at the fast law of thermodynamics.
00:12
Delta u is q add w where we rearrange for q, which is the heat is delta u minus w, where delta u is the change in internal energy.
00:22
W is the work done.
00:24
Then we have w equals negative p delta v that we can sub in.
00:29
So q is delta u add p delta b.
00:34
We change is the product of pressure and volume can be represented as delta p.
00:39
Is p delta v add v delta p constant pressure that is delta p is zero the equation becomes delta pv equals p delta v so then we applied this relation into the third equation we looked at we get q p delta u add delta p v where q p is delta u add p b where q p p is delta u add p b where q p b where q p is delta u add p b where qp is delta h and qp is h bar naught 3 ,000.
01:22
Take away h bar not 298 kelvin, where h bar not 3 ,000 subtract h bar not 298 kelvin is equal to the integral within the limits 3 ,298 cp naught dt, where we can now move on to the next portion where we are determining this integral.
02:06
So we have h0 ,000 subtract 298 kelvin is the integral 500, 298 kelvin, 39 .376 joules per kelvin per mole...