00:01
For this question we'll use the henderson -hasselbalch equation where ph is equal to pka plus the log of the moles of acetate over the moles of acetic acid.
00:18
I know a lot of people like to use with the henderson -hasselbalch equation molarity acetate over molarity of acetic acid, but it's so much easier and equivalent to use a ratio of moles.
00:31
So we want to achieve a ph of 5 .22.
00:36
We'll set that equal to pka which will be the negative log of the ka value of acetic acid, 1 .8 times 10 to the negative 5.
00:46
We then add to that the log of the moles of acetate.
00:50
We start with a liter, so that's 1 .0 liters, at a concentration of 1 .2 moles per liter.
00:58
That's how many moles of acetate we have before the addition of sodium hydroxide.
01:06
Every mole of sodium hydroxide we add is going to react with the acetic acid and make more acetate and sodium and water.
01:25
So the moles of sodium hydroxide we add will be equivalent to the increase in the moles of acetate...