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How much solid $\mathrm{NaCH}_{3} \mathrm{CO}_{2} \cdot 3 \mathrm{H}_{2} \mathrm{O}$ must be added to 0.300 $\mathrm{L}$ of a $0.50-\mathrm{M}$ acetic acid solution to give a buffer with a pH of 5.00$?$ (Hint: Assume a negligible change in volume as the solid is added.)

37$g(0.27 \mathrm{mol})$

Chemistry 102

Chapter 14

Acid-Base Equilibria

Liquids

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let's calculate the amount of solid sodium acetate tri hydrate that needs to be added. 2.5 Mueller City Gas ID To give a buffer solution with a pH of 5.0 we can turn that into a drone IAM Iron morality, which is equal to 10 to the minus 5.0 And this would be equal to 1.0 times 10 to the negative. Five. Mueller We're told that the mill arat e of the acetic acid is five Mueller so worthy of ch three c o. H is 50 Mueller. And so let's set up our ice table here. Ch three c o h on this would be for the buffer. Weak acid. Age 30 and C H three c O minus. An initial change equilibrium If three old equilibrium is one times 10 to the negative five. This is 50 We have an X here zero, and this would be plus 1.0 times 10 to the negative five plus 1.0 times 10 to the negative five x plus 1.0 times 10 to the negative five and minus one times 10 to the negative five. This would work out to 0.49999 Que a here or a expression First h 30 ch three c o minus over ch three C o h. Looking up the value for K K. We see that it is equal to 1.8 times 10 to the negative five plug in our values here and we're going to go ahead and solve for X. I'm gonna put this into my equation solver here. And well, so what we're gonna come up with here one the numerator times 10 to the negative five and x plus one. I'm tend to the and they get a five going ahead and solving, and we'll go to to significant figures I get X is equal 2.90 Therefore, the mill arat E of the ch three c o minus is equal to 0.90 Uh, Moeller. So we've got, um, sodium try hydrates. So the mole's would be the equal would be equal. So in a ch three c o try hydrates, I wonder. One more ratio. This is 10.90 Moeller on. So we're gonna start with 90 moles per leader times. We're told that we have 300 leaders times the Moller Mass. Here, which will be 136 grams per mole on Mosul. Council leaders will counsel, and we'll be left here with 22 sig figs, Uh, 37 g. Therefore, we will need 37 g of sodium acetate. Try hydrates.

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