how-much-water-do-you-need-to-add-to-10-mathrmml-of-a-solution-of-hcl-with-a-ph-of-3-to-change-the-m

Name: how much water do you need to add to 10 mathrmml of a solution of hcl with a ph of 3 to change the m
Uploaded: 2020-10-16
Duration: 1 min 36 s
Channel: Numerade
Description: How much water do you need to add to 10 $\mathrm{mL}$ of a solution of HCl with a pH of 3 to change the $\mathrm{pH}$ to 6$?$

Question

How much water do you need to add to 10 $\mathrm{mL}$ of a solution of HCl with a pH of 3 to change the $\mathrm{pH}$ to 6$?$

David Collins · Accepted Answer

question Number four is a delusion question in reference to pH. The delusion. Corrupt question reference to pH forces you to understand how much of a change in the hydro knee um concentration occurs with a one unit change in pH. Because PH is a log based 10 scale, then a one unit change in pH corresponds to a tenfold change in the hydro knee, um, ion concentration. So if we are going to change our pH from 3 to 6, that&#x27;s a three pH unit change, which means it&#x27;s a 10 times 10 times 10 or a thousandfold decrease in the hydro knee. Um, concentration. The only way to get 1000 fold decrease in the hydro knee um, concentration is to have 1000 fold increase in the volume. 1000 fold increase of 10 mL is 10,000 mL or 10 liters, so we would have to dilute the 10 million leaders to 10 leaders. So the amount of water that we would need to add would be 9000, 9000, 900 and 90 mL. To get this Yeah,

Anatole Borisov · Answer

in this question, we&#x27;re told that we have a 0.1 point 01 leader solution off uh, H CEO and that it has a ph of two. And so we&#x27;re asked to figure out how much does it need to be diluted? How much water needs to be added to get this toe have a PH equal before and so we can actually immediately figure out the malaria tee off this HCL because we we don&#x27;t need to know any K. Is there anything that because HDL is a strong acid into so states essentially 100%. And so what that means is the concentration of hydroxide ion is going to be equal to the initial concentration of HCL because all of this happened like this whole react this year, actually basically 100% where all the initial HDL becomes H plus. And so we can use the value of PH equal to two to find the concentration HD A plus. Because we, by definition HD a plastic als 10 to the negative of the pH is so negative two. So that&#x27;s our That&#x27;s our answer for the concentration of age trio Plus And so now we&#x27;re going to use this in order to get to a point where we basically were were. We need to figure out how many moles of HBO plus there are in our 0.1 leaders and then from there, decide how much means water needs to be added in order to get this value to be tense, a negative force. And so if we take 10 to the negative second Moeller, so I&#x27;ll rewrite that as moles, her leader times our 0.1 leader we&#x27;re going to get, um, tends the negative fourth most cancel out these leaders. So that&#x27;s how much that&#x27;s how much hydroxide we have, which is also another way of saying just how much HCL we have. And so if we now our question is, how do we get from having hence the negative fourth moles of something? It should be potential for tens of negative fourth Moeller, and the reason we know we want this is because we&#x27;re told of them pH that we&#x27;re shooting for at the end is equal to four. And so, like we did before, we&#x27;re looking to have it 10 to the negative. PH is the conservation of hydro hydro name that we&#x27;re looking for so tense to negative four. So that&#x27;s why we&#x27;re look trying to get this amount. Tensor native, fourth moles to become Tense Inarritu, fourth Moeller And so this like it might seem like we&#x27;re just pushing this out too far. But what we&#x27;re really looking for is what volume makes this true. And very obviously it&#x27;s one leader because we just basically to divide mold by leader. It&#x27;s make it malaria. And so the answer, though, is not one leader is the amount that we need to add, because that&#x27;s like That&#x27;s the answer to the question. If it were, how much water is needed just in this certain amount of, um, HCL. But we&#x27;re supposed to get from 0.1 leaders to one leader, which do some subtraction in your head or in a calculator. 0.99 leaders past the answer that we&#x27;re looking for

David Collins · Answer

to calculate the pH of the diluted solution. We need to know what the concentration of HDL is in the diluted solution. So we&#x27;ll use the dilution equation. The morality of the diluted solution multiplied by the volume of the diluted solution, which is 100 mil. Leaders will be equal to the morality of the concentrated solution which is six Mohler multiplied by the volume of concentrated solution used, which is five mil leaders. And we get a morality of the diluted solution of 0.300 Mueller. Because HCL is a strong acid, the morality of the HCL solution is the molar ity of the hydrogen ion concentration. So we take the negative log of 0.3 and we get a pH of 0.25

David Collins · Answer

The best way to answer this question is to use the Henderson hassle Baulch equation. PH is going to be equal to P. K A. The acid that is present is going to be the ammonium that is created when we add the HCL to a solution already containing Maura Ammonia. So we need the PK of ah, ammonium. Here we can look up the K B of ammonia 1.8 times tend to negative five divided into K W. That will give us our K A. Will. Take the negative log of it and we&#x27;ll get PK so pH equals P K A plus. The log of the moles of base, the moles of base that we have after we add the HCL will be equal to the moles of base we start with which will be the volume 25 milliliters multiplied by the concentration 250.45 minus the moles of base that reacted and the moles of base. That react will correspond to the most of strong acid added. So we added 25 milliliters of 0.12 Moeller hcl. Then that will be divided by the moles of weak acid formed in the moles of weak acid form will be equal to the molds of strong acid added because not all of the week base ammonia was consumed. So it&#x27;ll be equal to the 0.25 which is the volume in leaders 25 milliliters converted to leaders multiplied by the molar ity of 250.12 Now this Henderson has The vault equation is a ratio of moles. Moles base over Mel&#x27;s acid, but remember, it could also be malaria t base over malaria. T Asset. I&#x27;ve chosen to just use moles here, and we get a pH of 9.67

Aadit Sharma · Answer

for this caution. We have a total off to parts but one on the butt, too. First, we need to calculate the number off moles off any which present in one leader off toe 10 m solution. Doing the calculations going. So the solution has two moons off in the village. For the second part, we need to calculate the concentration off. Was the divine at zero in the mixture? Yeah. Zero. There will be maximum concentration off its positive I in on. We have already known that there is no change in William and acid. That seal is added.

Anatole Borisov · Answer

So for the pH to be zero, Um, if we remember, the concentration of H 30 plus is equal to the 10 to the negative pH so tense and I give zero. Well, our consolation ratio plus has to be one one Moeller. And in this situation, we&#x27;re told that the volume is always equal to one leader and so the concentration of HBO plus that we need to get to If it&#x27;s one Moeller and we&#x27;re in 11 leader, we&#x27;re looking tohave one mole of age 30 plus No, Where are we have to begin? This is where we&#x27;re trying to get to while we&#x27;re starting with one leader of two Moeller o h minus now an a o h. But that&#x27;s the same the any closets a spectator ion. So we can multiply one leader by to mold to Moller and we are given that we have two moles of O. H minus. Um, this is a common story geometry. If you&#x27;re not comfort this uto, go back to your succulents practice. But so we have is we have two moles of O h minus and one mole of H 20 plus. Now what happens whenever you have O h minus and H 30 Claussen water. They will, uh, second equilibrium. But it drives really hard towards the right. They&#x27;re gonna neutralize each other, inform water and so we need is we need to add enough acid so that it cancels out. These o h minus is so in other words, we need to add two moles of HCL, which is grace. We just say a still plus Muto have strong acid. Plus, we need to still get that extra. Most of it get her ph down to zero. And so we need to plus one moles. So overall, our final answers that we need three moles of HCL gas to cancel out the O. H minus and then get the ph down here.

Problem

Explain why the $\mathrm{pH}$ of a $1 \times 10^{…

Problem 4 Easy Difficulty

How much water do you need to add to 10 $\mathrm{mL}$ of a solution of HCl with a pH of 3 to change the $\mathrm{pH}$ to 6$?$

Answer

$10,000 m L$

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