00:04
In this question, we are asked to calculate the amount of work that is required when it comes to moving an electron that is at an infinite distance from a proton to a distance of 0 .5 nanometer from the proton.
00:27
So to calculate the work that goes into this setup, we can use this equation, which tells us that the work involved here is equal to 1 over 4, 5, epsilon, which is the permittivity of a vacuum, and then epsilon r, which is the relative permittivity of the media that this is occurring in.
00:59
And then we have to multiply this by the charge of the first particle, the charge of the second particle, and then divide it by r, which is the distance or the final distance between the two particles.
01:14
So because we are not told what media this is occurring in, we are going to assume that this is occurring in a vacuum.
01:22
So we're going to get rid of the upside and r part because in a vacuum it's going to be equal to 1.
01:30
And the other thing we have to note here is that the charge of an electron is equal to the charge of a proton.
01:40
And that is equal to 1 .602 times 10 to the negative 19 colon.
01:48
So instead of q1 and q2, q1 times q2, i'm going to just use 1.
01:57
0 .602 times 10 to the negative 19 column and take the square of that.
02:08
And as we discussed, r is the final distance between the two charged particles, which is going to be 0 .5 nanometer...