00:01
In this video, we are going to focus on finding the shape of the sampling distribution, mean of the sampling distribution, as well as standard deviation of the sampling distribution based on the given information.
00:11
So here the sample size for the first sample is 16, then the sample size for the second sample is 9, and then here we can write that mu 1 value, that is mean for first sample is 69 .3, and then mu 2 value will be here equals to 64 .5.
00:30
Then we can say that the value of sigma 1, that is standard deviation will be here, 2 .8, and then here we can say that value of sigma 2 will be equals to 2 .5.
00:40
So we have been given that the population distribution of the first normal, sorry, first population is normal and the population distribution of second population is also normal distribution.
00:51
Since both, let's write over here that both distributions, d -i -t -r -i, b -u -t -i -o -n -s are normal.
01:04
So, the shape of the sampling distribution will also be normal.
01:09
So here we can write that shape will be equals to, so we are talking about the shape of x -m -m -minus, it is x -w, right? and it can equivalently return as, here it will be x -1 -1 -6 -2 -bar.
01:26
So it is x1 bar minus x2 bar basically.
01:30
And then this very value, we can say that the shape is here equals to normal for the sampling distribution as well.
01:38
And this is the answer for the first part of this very problem.
01:41
And we can put this thing inside a box and it will look like this...