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$\mathrm{H}_{3} \mathrm{BO}_{3}$ is a monobasic a…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20

Problem 19 Easy Difficulty

How would you prepare the following compounds:
(a) $\left[\mathrm{IF}_{\mathrm{e}}\right]^{+}\left[\mathrm{SbF}_{6}\right] ;$; (b) carbon suboxide; (c) $\mathrm{X}_{\theta} \mathrm{O}_{3} ?$
(Sections 27.3, 27.6, 27.7)

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Chemistry 101

Chemistry $^{3}$ : Introducing inorganic, organic and physical chemistry

Chapter 27

$p$-Block chemistry

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Nonmetals Chemistry

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Video Transcript

Hello everyone. Let us see the following question. How would you prepare the following compounds? So in sub question eh We have given the following compound, that is IEF six, I F six class and SV E F six minus. See this coordination compound would have been got from the respective lewis acid and base. So definitely I Yes. Seven. Okay. All right. Yes be. Yes. Right, so here we know that there is excess of fluoride on my audience. So this would act as lewis base and this is louis as I would give corresponding complex sort. So let us find out about option B where we have to prepare carbon sub oxide. So what is carbon sabak side? So carbon sub oxide has a formula of C three. So C 302 which we get from the corresponding carb oxalic acid group. That means C O H. Ch two and C O H. So this is mel annoyed cassie with P. For oh then it will give carbons a boxer Plus Force 40 cast at age three B 04. So on balancing, we have to balance here. So phosphoric acid is P here so P four is already here. So we have to multiply four to phosphoric acid, hydrogen becomes too well. So already there is two plus 345. So let us multiply three. So that here 15. So here already for Teresa to L. A. There So any other cont anything carbon is three. So here already we are multiplying three. So let us multiply three, oxygen, 10, oxygen 16 plus. Okay. Uh 10 It is 12344, 3 that well, yes it is balanced. So let us see. So this is carbon Suboxone. It is prepared from melon oy Cassidy. So this is melody. No weak. Ah yes sir, our propane one comma two Cassidy. So this is carbon, some oxide. So let's see about the option C. In option C. We have to prepare XC. So XE 03 is prepared from highlights of Xenon. So from Xenon tetra chloride on hydraulics sis H two. So it gives Xenon Proxy. Xenon also gives oxygen and HF. So on balancing it must be six here, it must be too well here, two, here for Here three and here 24. So the xenon trioxide is prepared from xenon tetra flow. Right, thank you.

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Andrew Burrows, John Holman, Andrew Parsons

Chemistry $^{3}$ : Introducing inorganic, organic and physical chemistry

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