00:01
Okay, so we've got three molecules here that we have to make only from benzene.
00:07
So we're going to start with benzene.
00:12
And you'll notice that the relationship between the substituents is para.
00:15
So the way that i approach these is identify the relationship between the substituents, then look at the substituents and see if either of the groups that you can add will direct that second group to the position that is at.
00:29
So the chlorine group is a deactivator, but it's orthoparidirecting.
00:35
But you don't know of a way to add a vinyl group.
00:39
You can't do frito -crafts with a vinyl chloride because the carbocadion, the vinyl cation is too high in energy.
00:48
So you can add an ethyl group, though, right? you know how to add afl groups.
00:55
And then you'll have to find a way to remove two of those hydrogen atoms.
01:01
So i'm going to go ahead and add the ethel group first, only because the ring will be more activated for chlorination.
01:16
You'll probably end up getting a polysubstituted, a diethylbenzine just based off over the poly substitution.
01:26
Right? that's what the book says.
01:32
This ring is more active for a second frito crafts with another ethel group.
01:38
So now we can chlorinate and assuming that we can separate our ortho and para products.
01:47
Assume we could separate the monoethylbenzine from the diethylbenzine initially.
01:53
So now we're left with something that somewhat resembles our product.
01:56
We have to figure out how to lose the saturation in the ethel group now.
02:02
So you know of a reaction that would allow you to add a leaving group here.
02:08
And that's going to be free radical bromination at the benzal position.
02:16
Right.
02:16
So you can use a reagent called nbs.
02:20
In the presence of some organic peroxide, generally those ours are, usually you would use benzoyle peroxide is what the book uses.
02:36
You just need a radical initiator.
02:38
That's going to add a single bromine to the benzol position.
02:44
And that will give us our leaving group, right? and then you can go ahead and do an e2, which will form that, which will pluck off the proton here.
02:54
So i went ahead and i just used sodium methoxide to do that in methanol.
03:02
Fine.
03:04
And that will give us, that will give us the unsaturated product.
03:08
Cool.
03:09
So now we have this symmetrical alcohol here.
03:13
So we have a para ch2 -o -h group on the ring.
03:19
So how are we going to add those? well, you can't do, you wouldn't be able to do, or the textbook didn't show you any examples of doing fidel crafts when you have some other substituent close enough to, like you don't, you haven't seen an example like this, for example.
03:43
So we probably we can't do that.
03:47
We can do something similar to what we just did, though, right? so we could add the alcohol groups first.
03:54
You know the relationship is para.
03:56
So if you add an alcohol group, maybe like methyl chloride and aluminum chloride, you'll probably end up getting the paramehyl.
04:04
You probably end up making p.
04:05
Zyline anyway.
04:07
So you can use two equivalents just to make more of it, i guess.
04:12
But even if you add one equivalent, you know poly substitution is preferred.
04:16
Then something we can do is we can do two equivalents of nbs again with the organic peroxide.
04:24
That will give us bromines at both of those benzopositions.
04:31
Sorry, i just made an extra carbon.
04:35
I was reminding myself of the last problem.
04:39
And then i just did it again.
04:45
And then the last thing that you would probably have to do is an ethyl, an sn2 with a hydroxide...