00:01
Okay, so in this problem, we're given a combustion reaction, and this reaction consists of hydrogen gas and methane gas.
00:09
And we're given both the respective heats of combustion per, it's given in joules per gram of substance.
00:18
So we're going to go ahead and determine that.
00:22
Ultimately, the question is saying that we're going to run this combustion reaction and transfer the heat given off to water and they want us to figure out what is the final temperature of the water and they give us things such as mass and the initial temperature.
00:40
So we'll go ahead and figure out what that change in temperature is and then ultimately we can find the final temperature of that water.
00:47
So first of all, we're given the values hydrogen gas for every one gram that's burned in this reaction.
00:55
We have 120 joules worth of energy released and then for methane, we have for every one gram of substance burns, we have 50 joules worth of energy.
01:07
So from there, they give us 5 grams of hydrogen and 10 grams of methane are given in this reaction.
01:15
So we simply need to find those respective heats given off and just combine them together.
01:22
So we'll do that first.
01:23
Then we know how much heat was evolved.
01:26
And that's the same amount of heat that is transferred over to the water.
01:30
And again, we assume that none of that is released or lost to the environment.
01:37
And from there, this is to figure out our heat.
01:42
And then from there, we'll use q equals mc delta t.
01:46
And ultimately, we're just trying to find this guy over here.
01:51
We're trying to find out what is our delta t.
01:54
We have mass.
01:55
We have specific heat.
01:57
That's a known data quantity.
01:59
And we do have our initial temperature as well.
02:03
Our t .i.
02:04
Is 25 degrees celsius.
02:10
Okay, so we'll go back to the second screen real quick.
02:13
So we have five grams of hydrogen, and i know 120 joules will be released per one gram.
02:23
So for hydrogen, we know we have 600 joules released, and then we're given 10 grams of the methane.
02:32
That's the m down here.
02:33
M is for the methane.
02:36
And we have 50 joules per gram here...