00:02
Let us start with option a and the presentation of reaction.
00:08
We have ch4 plus water gives carbon monoxide plus 3 hydrogen 2.
00:20
The standard enthalpy of formation for above compound, that is, ch4, is negative 75 kilojoule per mole, while for water it is negative, while for water it is negative 242.
00:45
Overall, the enthalpy delta h for reactants, it is an addition of ch4 and water.
00:59
So negative 75 plus negative 242 which gives us negative 317 kilojou.
01:10
Similarly, for products, carbon monoxide, it is negative 110 .5 kilojoule per mole, while for three moles of hydrogen, it is zero kilojoules.
01:31
So, delta h for products, p for product, it is negative 110 .5 kilojoules.
01:41
Therefore, the standard enthalpy formation for the overall reaction is the enthalpy of products minus the enthalpy of our reactants goes as negative 110 .5 minus 317 kilojoules equals 206 .5 kilojoules.
02:10
Similarly the standard entropy of a reaction and entropy is delta s standard entropy or overall entropy for the reaction is entropy of product minus the entropy of reactants so entropy for ch4 is 86 water 189 they are all in jule per kelvin mole...