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(I) A car accelerates from 12 $\mathrm{m} / \mathrm{s}$ to 21 $\mathrm{m} / \mathrm{s}$ in 6.0 $\mathrm{s}$ . Whatwas its acceleration? How far did it travel in this time?Assume constant acceleration.

$99 \mathrm{m}$

Physics 101 Mechanics

Chapter 2

Describing Motion: Kinematics in One Dimension

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

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Lectures

03:28

Newton's Laws of Motion are three physical laws that, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces. These three laws have been expressed in several ways, over nearly three centuries, and can be summarised as follows: In his 1687 "Philosophiæ Naturalis Principia Mathematica" ("Mathematical Principles of Natural Philosophy"), Isaac Newton set out three laws of motion. The first law defines the force F, the second law defines the mass m, and the third law defines the acceleration a. The first law states that if the net force acting upon a body is zero, its velocity will not change; the second law states that the acceleration of a body is proportional to the net force acting upon it, and the third law states that for every action there is an equal and opposite reaction.

04:16

In mathematics, a proof is a sequence of statements given to explain how a conclusion is derived from premises known or assumed to be true. The proof attempts to demonstrate that the conclusion is a logical consequence of the premises, and is one of the most important goals of mathematics.

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so here. By definition, we confined the acceleration. This would be equal to the change in velocity divided by the change in time. Ah, this would be equal to 21 meters per second, minus 12 meters per second, divided by the time it took to reach 21 muse per second from 12 meters per second. So this will be 6.0 seconds and this is equaling one 0.5 meters per second squared. Now. If it's asking for the total time, the rather the total distance traveled within sex sex six seconds. We can say howto act equals v X initial times t plus 1/2 times a T squared and we can solve by substituting directly. So the ah, the ex initial would be equal to 12 meters per second, multiplied by again 6.0 seconds plus 1/2 times 1.5 meters per second squared multiplied by 6.0 seconds. Quantity squared and Delta X is found to be equal to 99 meters. So this would be our total distance rather than total displacement and our acceleration. That is the end of the solution. Thank you for watching

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