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(II) The momentum of a particle, in SI units, is …

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104 Problem 105 Problem 106 Problem 107 Problem 108 Problem 109 Problem 110 Problem 111 Problem 112 Problem 113 Problem 114

Problem 2 Easy Difficulty

(I) A constant friction force of 25 $\mathrm{N}$ acts on a 65 -kg skier for 15. S. What is the skier's change in velocity?

Answer

$-5.8 m / s$

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Physics 101 Mechanics

Physics for Scientists and Engineers with Modern Physics

Chapter 9

Linear Momentum

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Video Transcript

the average force is given by the rate of change momentum. Delta P A riddle to tea on DSO Delta P is just mass times the raid times of change in velocity on That's divided by Delta two. Okay, so in this problem were given force and mass in time. We want adult of you so full the friction saw it will opposed will be in the opposite direction. To the direction of motion will be a negative negative. 25 Newton's That's equal to Mass, which is 65 kilograms times Delta V, which we don't know over Delta T, which is 15 seconds. Therefore, Delta V is just 25 times 15 over 65. This will be in meters per second and we get, um, are negative 25 times now and we get minus 5.8 meters per second. Therefore velocity was 5.8 meters per second. Was a velocity lost

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Douglas C. Giancoli

Physics for Scientists and Engineers with Modern Physics

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