00:01
In this problem, we're asked to consider the investigation of j.
00:04
A.
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Moore into the inheritance of spotty patterns and leopard frogs.
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The pipians phenotype has normal spots that give the leopard frogs their name.
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In contrast, i think it's the bernsey phenotype, lacked spots on its back.
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And moore carried out the following crosses, producing the progeny indicated.
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For question a.
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Based on results.
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Burns, bernsie phenotype most likely inherited, or is the, is the bernsie phenotype most likely inherited as dominant or recessive? okay, i see that this has to be dominant.
01:33
Look at the bernsey, bernsie crossed, produced pipians, which must be recessive.
01:59
Okay, next question.
02:05
B.
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I give most likely genotypes for each cross.
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And we're going to use b for burns, bernz, and b.
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Plus for, is it burz? burzzi? i can't tell what it is.
02:53
Maybe it's berzi.
02:57
Burzzi? okay, for pippian.
03:12
Pippians.
03:16
I'm going to go to the next page for this.
03:19
So we've got one, two, and three.
03:24
So here i'll have b and b plus, b and b plus.
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And that's needed for my recessive.
03:47
So recessive b plus can be produced.
03:56
My next one, i'm going to have b plus.
04:01
What was my next one? i've got way more pippians.
04:06
So i'm going to have a b plus b plus for my pipians.
04:13
I'm going to have a b and b plus.
04:25
What am i doing here? most likely genotypes.
04:28
Let me read this question again.
04:30
Most likely of the parent cross.
04:39
Okay, there we go.
04:46
And then my last one, i have 196, so i think that i will go with the same on that one.
05:01
Those are my parent crosses.
05:02
Then last but not least, what do we have here? use the kye square test to evaluate the fit of observed to expected numbers of progeny.
05:50
Okay.
06:00
So my kye square formula will be equal to x squared equals my observed minus my expected divided by my expected.
06:20
Okay, so let's do our bernsy, bernsy.
06:38
This will be observed is 39b and 6p, pip, and bu.
06:54
My expected will be 30 and 15.
07:17
Okay, so this will be, so i'll expect b, b plus, bb, b, b, b plus, and b plus b plus.
07:48
So i'll expect there's these two types of genotype, these two to go together.
07:54
So this is one -third.
07:59
So i'm going to have, this will be, for my phenotypes, i'll have two phenotypes...