(i) A slab of thickness $L$ is initially at a uniform temperature $T_{0}$. The back face at $x=0$ is perfectly insulated. At time $t=0$, a laser deposits an amount of energy $E$ per unit area on the face at $x=L$. Determine the temperature response. (Hint: Let $\theta(x, t)$ be the temperature response for a unit uniform surface heat flux obtained by setting $q_{s}=1$ in the result of Exercise 3-86, part (i). Then, following part (ii) of Exercise 3-86, show that the required temperature response is
$$
T-T_{0}=E \frac{\partial \theta(x, t)}{\partial t}
$$
by imposing a heat flux $q_{s}$ for time $\Delta t$ and then letting $\Delta t \rightarrow 0$ such that $q_{s} \Delta t=E$.)
(ii) Hence show that the time for the back-face temperature rise to equal half of its maximum rise is $t_{1 / 2}=1.39 L^{2} / \pi^{2} \alpha$.