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(I) A sprinter accelerates from rest to 9.00 $\mathrm{m} / \mathrm{s}$ in 1.28 $\mathrm{s}$ .What is her acceleration in $(a) \mathrm{m} / \mathrm{s}^{2} ;(b) \mathrm{km} / \mathrm{h}^{2} ?$

a) $7.03 m / s^2$b) $9.11 \times 10^4 km / h^2$

Physics 101 Mechanics

Chapter 2

Describing Motion: Kinematics in One Dimension

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

University of Washington

Simon Fraser University

McMaster University

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we have a sprinter that's accelerating from rest. So that means the initial velocity zero and sprinter accelerates to nine meters per second in 1.28 seconds. So v of 1.2 wait is nine meters per second and we want to find the acceleration, which is just Delta V over Delta T. So, uh, you want V of 1.28 minus 50 over changing time, which is just nine minus zero over 1.28 And this equals 7.3 municipal second squared. And now if you want this in kilometers per hour, squared uh, the little dimensional analysis. First, I'll deal with the meters. So I have one Kilometer is 1000 meters some meters cancel and then to go from second square toe our squared one squared, our squared is 3600 squared, second squared and I could just two hours. And this is 9.11 times 10 to the fourth kilometers per hour. Squid

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