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(I) Calculate the acceleration due to gravity on the Moon.The Moon's radius is $1.74 \times 10^{6} \mathrm{m}$ and its mass is$7.35 \times 10^{22} \mathrm{kg}$

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1.62 $\mathrm{m} / \mathrm{s}^{2}$

Physics 101 Mechanics

Chapter 6

Gravitation and Newton's Synthesis

Physics Basics

Newton's Laws of Motion

Applying Newton's Laws

Gravitation

Cornell University

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

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Lectures

03:43

In physics, dynamics is the branch of physics concerned with the study of forces and their effect on matter, commonly in the context of motion. In everyday usage, "dynamics" usually refers to a set of laws that describe the motion of bodies under the action of a system of forces. The motion of a body is described by its position and its velocity as the time value varies. The science of dynamics can be subdivided into, Dynamics of a rigid body, which deals with the motion of a rigid body in the frame of reference where it is considered to be a rigid body. Dynamics of a continuum, which deals with the motion of a continuous system, in the frame of reference where the system is considered to be a continuum.

03:55

In physics, orbital motion is the motion of an object around another object, which is often a star or planet. Orbital motion is affected by the gravity of the central object, as well as by the resistance of deep space (which is negligible at the distances of most orbits in the Solar System).

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(II) Calculate the acceler…

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Find the acceleration due …

The The mass of the moon i…

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Repeat the calculation in …

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The acceleration due to gr…

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Mass of moon is $7.34 \tim…

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Use the formula from Exerc…

so we simply have to calculate the ah ahs acceleration due to gravity on the moon. We can say that the force of gravity on with a person that isn't moving on the moon's surface We could say that the only force on the mass would be force of gravity. This would be equal to the universal gravitational, constant times the mass of the moon times the mass of the person standing on top of the moon, divided by ah, the radius of the moon squared. And this would simply be equal. Teo. The force of gravity would also be equal to M g due to the definition of the force of gravity. And this would be the mass of the person times the gravity on the moon. You, Khun, tell you just by looking at the equation we know that masses cancel out. So the mass of the person is not relevant here and we can say that the gravity on the moon's surface would be equal to the universal gravitational constant times The mass of the moon, divided by the radius of the moon, squared and weaken solve, so the gravity on the moon would be equal to 6.67 times 10 to the negative, 11th times the mass of the moon, 7.35 times, 10 to the 22nd kilogram. And then this would be divided by the radius of the moon. Squared 1.74 times, 10 to the sixth meters. Quantity squared. And we have that the gravity of the acceleration of gravity on the moon would be 1.62 meters per second squared. This would be our final answer. That's the end of the solution. Thank you for watching.

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