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(I) Calculate the speed of a satellite moving in a stablecircular orbit about the Earth at a height of 5800 $\mathrm{km} .$

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$5.72 \times 10^{3} \mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 6

Gravitation and Newton's Synthesis

Physics Basics

Newton's Laws of Motion

Applying Newton's Laws

Gravitation

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03:43

In physics, dynamics is the branch of physics concerned with the study of forces and their effect on matter, commonly in the context of motion. In everyday usage, "dynamics" usually refers to a set of laws that describe the motion of bodies under the action of a system of forces. The motion of a body is described by its position and its velocity as the time value varies. The science of dynamics can be subdivided into, Dynamics of a rigid body, which deals with the motion of a rigid body in the frame of reference where it is considered to be a rigid body. Dynamics of a continuum, which deals with the motion of a continuous system, in the frame of reference where the system is considered to be a continuum.

03:55

In physics, orbital motion is the motion of an object around another object, which is often a star or planet. Orbital motion is affected by the gravity of the central object, as well as by the resistance of deep space (which is negligible at the distances of most orbits in the Solar System).

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(I) Calculate the speed of…

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Calculate the speed of a s…

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Find the speed of a satell…

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Finding satellite speed A …

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A satellite moves in a cir…

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What is the speed of a sat…

we want to calculate the speed of satellite 5800 kilometres above the earth's surface. So are is going to equal the radius of the earth plus 5800 kilometres. This's giving us 1.218 times 10 to the seventh meters. From here, we can say that the force of gravity is going to be equal to the mass times. Ian Centripetal acceleration. Given that this satellite is experiencing uniform circular motion, we can say that this is equaling and be squared over r. And the force of gravity is going to be equal to their gravitational constant times. The mass of the satellite times the mass of Earth divided by r squared. So in this sense that we can say that philosophy is going to be equal to the gravitational, constant times the mass of the earth divided by the radius, or rather the distance from the satellite to the center of the Earth to the 1/2 power and we can solve So V is going to be equal to 6.67 times 10 to the negative 11th. The mass of the earth is 5.98 times 10 to the 24th kilograms and then this will be divided by the distance from the satellite to the center of the earth, 1.218 times, 10 to the seventh meters, quantity to the 1/2 power. And we can say that the velocity of the satellite 50 100 kilometres above the earth's surface, is going to be 5.72 times 10 to the third meters per second. So this is our final answer. That is the end of the solution. Thank you for watching.

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