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I) How much tension must a rope withstand if it is used to accelerate a 1210-kg car horizontally along a frictionless surface at 1.20 m/s$^2$ ?

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Donald A.

Physics 101 Mechanics

Chapter 4

DYNAMICS: NEWTON'S LAWS OF MOTION

Section 4

Newton's Second Law of Motion

Newton's Laws of Motion

Applying Newton's Laws

Sharieleen A.

October 27, 2020

I've been struggling with Physics: Principles with Applications, this is so helpful

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What the force on the rope is going to be the mass of the car times the acceleration Mass is 1210 kilograms, Acceleration is 1.20 meters per second squared. Um, and that's gonna be the same as the tension. So just putting that into a calculator, 1210 times 1.2 is 1000, 450 newton's. There are only three significant digits, Okay?

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