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(I) How much work must be done to stop a 1300 -kg car traveling at 95$\mathrm { km } / \mathrm { h }$ ?

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$-4.5 \times 10^{5} \mathrm{J}$

Physics 101 Mechanics

Chapter 7

Work and Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

Cornell University

Simon Fraser University

McMaster University

Lectures

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In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

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In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

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(I) How much work must be …

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How much work must be don…

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A $1200-\mathrm{kg}$ autom…

A 1200 -kg automobile trav…

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A car of mass $m=1250 \mat…

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A car $(m=1200 \mathrm{kg}…

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(II) What average force is…

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What average force is requ…

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$\cdot$ $\cdot$ Stopping d…

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$\cdot$ How much work is n…

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The mass of a car is $1000…

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A $1250-\mathrm{kg}$ car m…

7.53. So we'll have. We have a car that's moving at 95 kilometers per hour and its mass is 1300 kilograms. We want to know how much work we have to do to stop it. So the work is going to be the change in kinetic energy. So the final kinetic energy is going to be zero if it stopped. So the amount of work we have to do is equal to its initial kinetic energy 1/2 and b squared. So the final is zero minus the initial. And so this is negative 4.5 times 10 to the fifth Jules making sure to convert kilometers per hour two meters per second.

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