(i) If $Z_{i} \cong \mathbb{Z}$ for all $i$, prove that
$$
\operatorname{Hom}_{\mathbb{Z}}\left(\prod_{i=1}^{\infty} Z_{i}, \mathbb{Z}\right) ¥ \prod_{i=1}^{\infty} \operatorname{Hom}_{\mathbb{Z}}\left(Z_{i}, \mathbb{Z}\right)
$$
Hint. A theorem of J. Los and, independently, of E. C. Zeeman (see Fuchs, Infinite Abelian Groups II, Section 94) says that
(ii) Let $p$ be a prime and let $B_{n}$ be a cyclic group of order $p^{n}$, where $n$ is a positive integer. If $A=\bigoplus_{n=1}^{\infty} B_{n}$, prove that
$$
\operatorname{Hom}_{k}\left(A, \bigoplus_{n=1}^{\infty} B_{n}\right) \neq \bigoplus_{n=1}^{\infty} \operatorname{Hom}_{k}\left(A, B_{n}\right)
$$
Hint. Prove that $\operatorname{Hom}(A, A)$ has an element of infinite order, while every element in $\bigoplus_{n=1}^{\infty} \operatorname{Hom}_{k}\left(A, B_{n}\right)$ has finite order.
(iii) Prove that Hom $_{2}\left(\prod_{n \geq 2} \mathbb{I}_{n}, \mathbb{Q}\right) \neq \prod_{n \geq 2} \operatorname{Hom}_{\mathbb{Z}}\left(\mathbb{I}_{n}, \mathbb{Q}\right)$.