The general equation of a conic is $Ax^{2}+2Hxy+By^{2}+2Gx+2Fy+C=0$. Comparing this with the given equation, we get $A=12$, $H=\frac{7}{2}$, $B=-10$, $G=\frac{13}{2}$, $F=\frac{45}{2}$, and $C=-23$.
The condition for the conic to be a hyperbola is $H^{2}-AB>0$.
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